Sunday, 25 November 2012

SPM bio MRSM P2 Section B

Hi students,

Thank God i finally get a new laptop to work on.  I will send you the answer for section B via email by end of today, pls check your email.  If you do not get them, pls contact your friend/s to forward a copy of the answer.  Most probably you did not give me a valid email. 

All the best!

Best rgds,
teacher Sharon
Subang Jaya

Saturday, 10 November 2012

2012 MRSM Paper 3 (Answer)

Question 1:
a)      94, 62, 46
b)      i)
1. The volume of urine collected after taking distilled water is 94ml.
2. The volume of urine collected after taking 10.0% of drinking water is 46ml.
1. The volume of urine collected is the highest after taking distilled water because osmotic pressure decreases, volume of water reabsorb at the kidney tubule decreases.
2. The volume of urine collected is the lowest after taking 10.0% drinking water because osmotic pressure increases, volume of water reabsorb  at the kidney tubule increases.
c)       MV: Concentration of drinking water   à use different concentration of drinking water.
RV: volume of urine collected à measure and record the volume of urine collected by using a measuring cylinder.
CV: Volume of drinking water
à fix the volume of drinking water at 500ml.
d)      The higher the concentration of drinking water, the lower the volume of urine produced.
e)      I)
Concentration of drinking water (%)
Volume of drinking water (ml)
Volume of urine collected (ml)
Percentage of water reabsorbed by kidney (%)

f)       As the concentration of drinking water intake increases, the percentage of water reabsorbed increases.  This is because the osmotic pressure increases, therefore volume of water reabsorb increases.
g)      The volume of urine collected will be more than 94ml.  this is because caffeinated drink causes the volume of water reabsorb at the kidney tubule decreases.
h)      Osmoregulation is a process of maintaining osmotic pressure of the blood which can be determine by the volume of urine collected ; the volume of urine collected is affected by the concentration of drinking water.
Drinking cup
Sodium chloride solution
Measuring cylinder
Urine collected

Question 2:
Problem statement: What is the effect of concentration of carbon dioxide on the rate of photosynthesis of Hydrilla sp.
Hypothesis: The higher the concentration of carbon dioxide, the higher the rate of photosynthesis of Hydrilla sp.
MV: Concentration of carbon dioxide
RV: Number of air bubbles release in 10 minutes
CV: Light intensity  OR  distance of Hydrilla sp. Plant from the light source
Apparatus:  Glass funnel, light source, 60W bulb, beaker( 500ml), stopwatch, meter ruler, thermometer.
Material: Hydrilla sp., plasticine, distilled water, sodium hydrogen carbonate 2%, 4%, 6%, 8%.
Experimental Procedures: pls refer to your reference book/form 4 notes for procedures.
Presentation of Data: 
Concentration of sodium hydrogen carbonate  (%)
Number of air bubbles release in 10 minutes
Rate of photosynthesis (min-1)




Tuesday, 30 October 2012

SPM Bible Knowledge

SPM Bible Knowledge Paper

Teachers Christian Fellowship BK SPM

'"The Lord bless you
and keep you;
The Lord make his face shine upon you;
and be gracious to you;
The Lord turn his face toward you
and give you peace."'
Numbers 6: 24-26

Monday, 29 October 2012

Every moment Thanking God

Happy Moments.....Praise God.
Difficult Moments..... Seek God.
Quiet Moments...... Worship God.
Painful Moments..... Trust God.
Every Moment, Thank God.

Saturday, 27 October 2012

Perfect Score SPM Biology

Perfect Score Biology 2011
Question paper 2 & 3

On page 20
Diagram 10: L's wife and L's daughter are both normal female!
On page 21
Question 10 c(i): state the genotypes and gametes for the parents in the second generation.

Answer paper 2 & 3

Page 56
Question 1(e)(i)
Height of coloured liquid is 3cm-1cm=2cm

Page 57
(h) responding apparatus is metre ruler, material is coloured liquid

Note: you might need to correct some answer on the answer scheme if it is necessary.

All the best!

Thursday, 25 October 2012

2012 Ramalan SPM Biology Paper 2

It is always best and safer to cover all chapters while doing your revision. 
However, you might want to pay more attention to the following chapters:
Form 4:
Chapter 2: organelles and their function/s. eg: mitochondrion, chloroplast, rough ER, Golgi apparatus.  Chapter 3: Plasma membrane, the type of transport, ie: osmosis, facilitated diffusion, simple diffusion, active transport.
Chapter 4: production of extracellular enzyme, enzyme & its characteristics, lock-and-key hypothesis, enzyme & its uses in industries.
Chapter 5: cell cycle & cell division, formation of cancer cells.
Chapter 6: healthy food pyramid, digestion and assimilation, balance diet, photosynthesis
Chapter 7: Respiration in plant, respiratory structure and gaseous exchange in human, insect, fish, frog.
Chapter 8: food chains and food web, colonisation and succession in a pond.
Chapter 9: deforestation, thinning of the ozone, acid rain.

Form 5:
Chapter 1: lymphatic system, immunity
Chapter 3: transmission of nerve impulses across the synapse
Chapter 4: menstrual cycle and hormones related to this cycle, family planning.
Chapter 5/6: drawing of a genetic cross diagram (Mendel's first law and second law), drawing of Punnet square. causes of variation.

All the best!

2012 MRSM Paper 2 Section A & B ANSWER

Many thanks to for their great effort to share so many questions and answers with all teachers and students, not forgetting also those who have take the effort to scan and share papers online that hv greatly benefit many. Thank you!

Please refer to the question papers which i hv handed out during our biology lesson. or download your papers at Or click HERE

Answer to Section A: 
* you can always get your school biology teachers to workout the answer as well, they hv enough experience to guide you through.  You can also improve the answer below if you find them lacking/unfit.

Q 1
a) i) Y = carrier protein, Z= phospholipid bilayer
ii) Facilitated diffusion
iii) * water soluble, * large molecule
iv) *Higher concentration gradient,*more carrier proteins, * large surface area,* higher temperature
b)i) semi-permeable membrane is a membrane that allows certain substances to pass through it freely while others cannot.
ii)*volume of visking tubing decreases, * the surrounding solution is hypertonic compared to the solution in the visking tubing, *water diffuse out into the surrounding solution by osmosis
c) visking tubing doesn’t has carrier protein/ATP
a) Producer: Hydrilla sp., Secondary consumer: duck/black beetle/small fish/…
b) Duck eats small fish in the pond.
c) *cellular respiration doesn’t occur, * therefore no ATP can be produced, *lotus plant cannot carry out active transport to pump mineral ions into the root.
d)*excessive fertilizer will be drained into the pond,*encourage rapid growth of algae,* eutrophication occurs,*algae covered the surface of pond, less light intensity can penetrate into the water to reach the submerged plant, *…..
e) Tadpole : 20,000kJ x 10% = 2,000kJ, Black beetle: 2,000kJ x 10% = 200kJ
a) Cell X: Anaphase, Cell Y: Anaphase I
b) X: produce new cells for growth/repair dead tissues
Y: produce gametes
c) * Homologous chromosomes separate and move to opposite poles of the cell,
* Chromosome number are halved.
d) *8 daughter cells, *number of chromosome = 4
e) drawing: - we hv practised this many times, u can refer back to those drawings.
 *Cell X: draw a diploid cell that contains 4 chromosomes (2 big and 2 small unduplicated chromosomes)
*Cell Y:  draw a haploid cell that contains 2 chromosomes (one big and one small chromosome, u can show crossing over if you like), chromosomes must be unduplicated and non-homologous)
f) *chromosomes cannot divide/separate correctly,*causing abnormalities  of chromosome in daughter cells.
a)i) cakes/chocolates/….
ii) *constipation,*take more food containing fibre
iii) *build new cells for growth and to replace damaged tissues,*for synthesis of enzyme, antibodies,*……(refer to form 4, chapter 6 – assimilation)
b) P: 2,250kJ, Q: 800kJ, R:14,500kJ
ii) *Rice is the source of energy for carrying out activities while meat is mainly used for growth,*At that age, they are more active and therefore need more energy, while the growth process at this age has slowed down/almost complete.
c)i) *carbohydrate
ii) *eat more proteins,*proteins is used to produce new cells for growth of foetus.
a) P: XaY, Q:XAX
ab) drawing of Punnet square – again we hv done this many times in class, pls refer to your previous answer.
* male gametes: Xa     and    Y
* female gametes : XA   and    X
acomplete the genotype and phenotype
c)*blood clot very slowly, * due to lack of blood clotting factors needed for blood clotting.
d) drawing of genetic cross diagram – we hv done this as well, pls check/refer to your chapter 6 notes and questions.
Parental phenotype:    Blood group A (father)       x      Blood group B (mother)
Parental genotype:                IA IA                                                         IB  IO
random fertilization:
F1 generation
phenotypic ratio:    1 blood group A:   1 blood group AB

All the best! 

2012 MRSM Paper 1 Question and Answer

For question paper, click  HERE or go to


1.B   2.A   3.A  4.B  5.A
6.D   7.C   8.B   9.C   10.B
11.A   12.C   13.A   14.D   15.A
16.A   17.C   18.D   19.C   20.A
21.B   22.A   23.C   24.A   25.D
26.B   27.C   28.C   29.D   30C
31.B.  32.D   33.A   34.D   35.A
36.B   37.C   38.B   39.A   40.D
41.C   42.D   43.B   44.C   45.C
46.D   47.B   48.B   49.A   50.D

For other states trial paper, you can go to....

All the best in your SPM examination.